2x^-2/5+3x^-1/5+1=0

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Solution for 2x^-2/5+3x^-1/5+1=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x^-1)/5+(2*x^-2)/5+1 = 0

3/5*x^-1+2/5*x^-2+1 = 0

t_1 = x^-1

2/5*t_1^2+3/5*t_1^1+1 = 0

2/5*t_1^2+3/5*t_1+1 = 0

DELTA = (3/5)^2-(2/5*1*4)

DELTA = -31/25

DELTA < 0

x belongs to the empty set

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